| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.48 |
| Score | 0% | 70% |
If a car travels 360 miles in 6 hours, what is the average speed?
| 60 mph | |
| 75 mph | |
| 35 mph | |
| 45 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)What is \( 2 \)\( \sqrt{27} \) - \( 9 \)\( \sqrt{3} \)
| -3\( \sqrt{3} \) | |
| 18\( \sqrt{3} \) | |
| -7\( \sqrt{81} \) | |
| 18\( \sqrt{81} \) |
To subtract these radicals together their radicands must be the same:
2\( \sqrt{27} \) - 9\( \sqrt{3} \)
2\( \sqrt{9 \times 3} \) - 9\( \sqrt{3} \)
2\( \sqrt{3^2 \times 3} \) - 9\( \sqrt{3} \)
(2)(3)\( \sqrt{3} \) - 9\( \sqrt{3} \)
6\( \sqrt{3} \) - 9\( \sqrt{3} \)
Now that the radicands are identical, you can subtract them:
6\( \sqrt{3} \) - 9\( \sqrt{3} \)What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?
| 41 | |
| 37 | |
| 39 | |
| 46 |
The equation for this sequence is:
an = an-1 + 3(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46
A triathlon course includes a 100m swim, a 50.9km bike ride, and a 5.9km run. What is the total length of the race course?
| 46.6km | |
| 37.5km | |
| 56.9km | |
| 39km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.1km + 50.9km + 5.9km
total distance = 56.9km
What is the distance in miles of a trip that takes 9 hours at an average speed of 35 miles per hour?
| 280 miles | |
| 315 miles | |
| 135 miles | |
| 50 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 35mph \times 9h \)
315 miles