ASVAB Arithmetic Reasoning Practice Test 549288 Results

Your Results Global Average
Questions 5 5
Correct 0 3.12
Score 0% 62%

Review

1

If the ratio of home fans to visiting fans in a crowd is 3:1 and all 49,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
27,333
33,750
24,000
36,750

Solution

A ratio of 3:1 means that there are 3 home fans for every one visiting fan. So, of every 4 fans, 3 are home fans and \( \frac{3}{4} \) of every fan in the stadium is a home fan:

49,000 fans x \( \frac{3}{4} \) = \( \frac{147000}{4} \) = 36,750 fans.


2

What is \( \frac{5}{3} \) + \( \frac{7}{11} \)?

60% Answer Correctly
1 \( \frac{4}{10} \)
1 \( \frac{4}{33} \)
2\(\frac{10}{33}\)
2 \( \frac{6}{11} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 11 are [11, 22, 33, 44, 55, 66, 77, 88, 99]. The first few multiples they share are [33, 66, 99] making 33 the smallest multiple 3 and 11 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{5 x 11}{3 x 11} \) + \( \frac{7 x 3}{11 x 3} \)

\( \frac{55}{33} \) + \( \frac{21}{33} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{55 + 21}{33} \) = \( \frac{76}{33} \) = 2\(\frac{10}{33}\)


3

If a mayor is elected with 68% of the votes cast and 64% of a town's 25,000 voters cast a vote, how many votes did the mayor receive?

49% Answer Correctly
8,160
9,280
10,880
10,400

Solution

If 64% of the town's 25,000 voters cast ballots the number of votes cast is:

(\( \frac{64}{100} \)) x 25,000 = \( \frac{1,600,000}{100} \) = 16,000

The mayor got 68% of the votes cast which is:

(\( \frac{68}{100} \)) x 16,000 = \( \frac{1,088,000}{100} \) = 10,880 votes.


4

What is the least common multiple of 6 and 10?

72% Answer Correctly
8
31
30
39

Solution

The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 have in common.


5

What is (c2)5?

79% Answer Correctly
5c2
c-3
c10
c3

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(c2)5
c(2 * 5)
c10