ASVAB Arithmetic Reasoning Practice Test 552521 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

What is \( \frac{3}{6} \) x \( \frac{4}{5} \)?

72% Answer Correctly
\(\frac{9}{25}\)
\(\frac{9}{35}\)
\(\frac{2}{5}\)
\(\frac{4}{63}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{6} \) x \( \frac{4}{5} \) = \( \frac{3 x 4}{6 x 5} \) = \( \frac{12}{30} \) = \(\frac{2}{5}\)


2

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

greatest common multiple

greatest common factor

absolute value

least common multiple


Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.


3

Solve for \( \frac{4!}{5!} \)

67% Answer Correctly
\( \frac{1}{5} \)
42
3024
15120

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{4!}{5!} \)
\( \frac{4 \times 3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5} \)
\( \frac{1}{5} \)


4

In a class of 19 students, 8 are taking German and 13 are taking Spanish. Of the students studying German or Spanish, 7 are taking both courses. How many students are not enrolled in either course?

63% Answer Correctly
18
17
5
15

Solution

The number of students taking German or Spanish is 8 + 13 = 21. Of that group of 21, 7 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 21 - 7 = 14 who are taking at least one language. 19 - 14 = 5 students who are not taking either language.


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

55% Answer Correctly

commutative property for multiplication

distributive property for division

commutative property for division

distributive property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).