| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
What is \( \frac{5y^5}{8y^2} \)?
| 1\(\frac{3}{5}\)y-3 | |
| \(\frac{5}{8}\)y3 | |
| \(\frac{5}{8}\)y7 | |
| \(\frac{5}{8}\)y2\(\frac{1}{2}\) |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{5y^5}{8y^2} \)
\( \frac{5}{8} \) y(5 - 2)
\(\frac{5}{8}\)y3
What is \( \sqrt{\frac{36}{36}} \)?
| 1 | |
| \(\frac{3}{5}\) | |
| 1\(\frac{3}{5}\) | |
| 1\(\frac{1}{2}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{36}{36}} \)
\( \frac{\sqrt{36}}{\sqrt{36}} \)
\( \frac{\sqrt{6^2}}{\sqrt{6^2}} \)
1
Which of the following is not a prime number?
2 |
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9 |
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7 |
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5 |
A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.
A tiger in a zoo has consumed 39 pounds of food in 3 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 117 pounds?
| 3 | |
| 4 | |
| 7 | |
| 6 |
If the tiger has consumed 39 pounds of food in 3 days that's \( \frac{39}{3} \) = 13 pounds of food per day. The tiger needs to consume 117 - 39 = 78 more pounds of food to reach 117 pounds total. At 13 pounds of food per day that's \( \frac{78}{13} \) = 6 more days.
On average, the center for a basketball team hits 35% of his shots while a guard on the same team hits 50% of his shots. If the guard takes 15 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 12 | |
| 17 | |
| 20 | |
| 13 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{50}{100} \) = \( \frac{50 x 15}{100} \) = \( \frac{750}{100} \) = 7 shots
The center makes 35% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{7}{\frac{35}{100}} \) = 7 x \( \frac{100}{35} \) = \( \frac{7 x 100}{35} \) = \( \frac{700}{35} \) = 20 shots
to make the same number of shots as the guard and thus score the same number of points.