ASVAB Arithmetic Reasoning Practice Test 55362 Results

Your Results Global Average
Questions 5 5
Correct 0 2.95
Score 0% 59%

Review

1

What is \( \frac{5y^5}{8y^2} \)?

60% Answer Correctly
1\(\frac{3}{5}\)y-3
\(\frac{5}{8}\)y3
\(\frac{5}{8}\)y7
\(\frac{5}{8}\)y2\(\frac{1}{2}\)

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{5y^5}{8y^2} \)
\( \frac{5}{8} \) y(5 - 2)
\(\frac{5}{8}\)y3


2

What is \( \sqrt{\frac{36}{36}} \)?

70% Answer Correctly
1
\(\frac{3}{5}\)
1\(\frac{3}{5}\)
1\(\frac{1}{2}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{36}{36}} \)
\( \frac{\sqrt{36}}{\sqrt{36}} \)
\( \frac{\sqrt{6^2}}{\sqrt{6^2}} \)
1


3

Which of the following is not a prime number?

65% Answer Correctly

2

9

7

5


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


4

A tiger in a zoo has consumed 39 pounds of food in 3 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 117 pounds?

56% Answer Correctly
3
4
7
6

Solution

If the tiger has consumed 39 pounds of food in 3 days that's \( \frac{39}{3} \) = 13 pounds of food per day. The tiger needs to consume 117 - 39 = 78 more pounds of food to reach 117 pounds total. At 13 pounds of food per day that's \( \frac{78}{13} \) = 6 more days.


5

On average, the center for a basketball team hits 35% of his shots while a guard on the same team hits 50% of his shots. If the guard takes 15 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?

42% Answer Correctly
12
17
20
13

Solution
If the guard hits 50% of his shots and takes 15 shots he'll make:

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{50}{100} \) = \( \frac{50 x 15}{100} \) = \( \frac{750}{100} \) = 7 shots

The center makes 35% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{7}{\frac{35}{100}} \) = 7 x \( \frac{100}{35} \) = \( \frac{7 x 100}{35} \) = \( \frac{700}{35} \) = 20 shots

to make the same number of shots as the guard and thus score the same number of points.