ASVAB Arithmetic Reasoning Practice Test 553915 Results

Your Results Global Average
Questions 5 5
Correct 0 3.66
Score 0% 73%

Review

1

Find the average of the following numbers: 15, 11, 15, 11.

75% Answer Correctly
11
17
13
12

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{15 + 11 + 15 + 11}{4} \) = \( \frac{52}{4} \) = 13


2

Solve for \( \frac{3!}{4!} \)

67% Answer Correctly
\( \frac{1}{210} \)
\( \frac{1}{4} \)
\( \frac{1}{9} \)
20

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{4!} \)
\( \frac{3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4} \)
\( \frac{1}{4} \)


3

What is the least common multiple of 3 and 9?

72% Answer Correctly
22
21
4
9

Solution

The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 have in common.


4

A triathlon course includes a 100m swim, a 50.2km bike ride, and a 12.3km run. What is the total length of the race course?

69% Answer Correctly
26.1km
29.9km
28.4km
62.6km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.1km + 50.2km + 12.3km
total distance = 62.6km


5

Which of the following is a mixed number?

82% Answer Correctly

\(1 {2 \over 5} \)

\({5 \over 7} \)

\({a \over 5} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.