ASVAB Arithmetic Reasoning Practice Test 554382 Results

Your Results Global Average
Questions 5 5
Correct 0 2.93
Score 0% 59%

Review

1

a(b + c) = ab + ac defines which of the following?

74% Answer Correctly

commutative property for multiplication

distributive property for division

commutative property for division

distributive property for multiplication


Solution

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.


2

What is \( 5 \)\( \sqrt{48} \) - \( 6 \)\( \sqrt{3} \)

38% Answer Correctly
-1\( \sqrt{3} \)
-1\( \sqrt{-7} \)
14\( \sqrt{3} \)
-1\( \sqrt{48} \)

Solution

To subtract these radicals together their radicands must be the same:

5\( \sqrt{48} \) - 6\( \sqrt{3} \)
5\( \sqrt{16 \times 3} \) - 6\( \sqrt{3} \)
5\( \sqrt{4^2 \times 3} \) - 6\( \sqrt{3} \)
(5)(4)\( \sqrt{3} \) - 6\( \sqrt{3} \)
20\( \sqrt{3} \) - 6\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

20\( \sqrt{3} \) - 6\( \sqrt{3} \)
(20 - 6)\( \sqrt{3} \)
14\( \sqrt{3} \)


3

If \( \left|y - 2\right| \) - 3 = -6, which of these is a possible value for y?

62% Answer Correctly
-7
7
-6
5

Solution

First, solve for \( \left|y - 2\right| \):

\( \left|y - 2\right| \) - 3 = -6
\( \left|y - 2\right| \) = -6 + 3
\( \left|y - 2\right| \) = -3

The value inside the absolute value brackets can be either positive or negative so (y - 2) must equal - 3 or --3 for \( \left|y - 2\right| \) to equal -3:

y - 2 = -3
y = -3 + 2
y = -1
y - 2 = 3
y = 3 + 2
y = 5

So, y = 5 or y = -1.


4

If there were a total of 450 raffle tickets sold and you bought 9 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
5%
17%
2%
1%

Solution

You have 9 out of the total of 450 raffle tickets sold so you have a (\( \frac{9}{450} \)) x 100 = \( \frac{9 \times 100}{450} \) = \( \frac{900}{450} \) = 2% chance to win the raffle.


5

The total water usage for a city is 10,000 gallons each day. Of that total, 28% is for personal use and 44% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?

58% Answer Correctly
1,600
6,000
8,250
8,750

Solution

44% of the water consumption is industrial use and 28% is personal use so (44% - 28%) = 16% more water is used for industrial purposes. 10,000 gallons are consumed daily so industry consumes \( \frac{16}{100} \) x 10,000 gallons = 1,600 gallons.