| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.07 |
| Score | 0% | 61% |
| 3.5 | |
| 1 | |
| 2.0 | |
| 9.0 |
1
Solve 5 + (4 + 5) ÷ 2 x 5 - 22
| \(\frac{2}{3}\) | |
| 2\(\frac{1}{2}\) | |
| \(\frac{2}{7}\) | |
| 23\(\frac{1}{2}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
5 + (4 + 5) ÷ 2 x 5 - 22
P: 5 + (9) ÷ 2 x 5 - 22
E: 5 + 9 ÷ 2 x 5 - 4
MD: 5 + \( \frac{9}{2} \) x 5 - 4
MD: 5 + \( \frac{45}{2} \) - 4
AS: \( \frac{10}{2} \) + \( \frac{45}{2} \) - 4
AS: \( \frac{55}{2} \) - 4
AS: \( \frac{55 - 8}{2} \)
\( \frac{47}{2} \)
23\(\frac{1}{2}\)
Charlie loaned Betty $700 at an annual interest rate of 8%. If no payments are made, what is the total amount owed at the end of the first year?
| $714 | |
| $735 | |
| $756 | |
| $742 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $700
i = 0.08 x $700
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $700 + $56What is (z2)4?
| z2 | |
| 2z4 | |
| z8 | |
| z6 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(z2)4How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 6 gallon tank to fill it exactly halfway?
| 5 | |
| 2 | |
| 9 | |
| 4 |
To fill a 6 gallon tank exactly halfway you'll need 3 gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:
cans = \( \frac{3 \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 2