ASVAB Arithmetic Reasoning Practice Test 556332 Results

Your Results Global Average
Questions 5 5
Correct 0 3.06
Score 0% 61%

Review

1

Which of these numbers is a factor of 56?

68% Answer Correctly
9
56
55
14

Solution

The factors of a number are all positive integers that divide evenly into the number. The factors of 56 are 1, 2, 4, 7, 8, 14, 28, 56.


2

What is \( \sqrt{\frac{81}{16}} \)?

70% Answer Correctly
2\(\frac{1}{4}\)
\(\frac{1}{2}\)
1
\(\frac{6}{7}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{81}{16}} \)
\( \frac{\sqrt{81}}{\sqrt{16}} \)
\( \frac{\sqrt{9^2}}{\sqrt{4^2}} \)
\( \frac{9}{4} \)
2\(\frac{1}{4}\)


3

What is -6y5 x 4y2?

75% Answer Correctly
-2y7
-24y7
-2y2
-24y5

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

-6y5 x 4y2
(-6 x 4)y(5 + 2)
-24y7


4

What is \( 8 \)\( \sqrt{48} \) - \( 4 \)\( \sqrt{3} \)

38% Answer Correctly
28\( \sqrt{3} \)
32\( \sqrt{16} \)
4\( \sqrt{48} \)
4\( \sqrt{144} \)

Solution

To subtract these radicals together their radicands must be the same:

8\( \sqrt{48} \) - 4\( \sqrt{3} \)
8\( \sqrt{16 \times 3} \) - 4\( \sqrt{3} \)
8\( \sqrt{4^2 \times 3} \) - 4\( \sqrt{3} \)
(8)(4)\( \sqrt{3} \) - 4\( \sqrt{3} \)
32\( \sqrt{3} \) - 4\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

32\( \sqrt{3} \) - 4\( \sqrt{3} \)
(32 - 4)\( \sqrt{3} \)
28\( \sqrt{3} \)


5

If all of a roofing company's 10 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 9 complete crews out on jobs?

55% Answer Correctly
11
8
15
9

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 10 workers at the company now and that's enough to staff 5 crews so there are \( \frac{10}{5} \) = 2 workers on a crew. 9 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 9 x 2 = 18 total workers to staff the crews during the busy season. The company already employs 10 workers so they need to add 18 - 10 = 8 new staff for the busy season.