ASVAB Arithmetic Reasoning Practice Test 556858 Results

Your Results Global Average
Questions 5 5
Correct 0 3.03
Score 0% 61%

Review

1

Solve for \( \frac{3!}{5!} \)

67% Answer Correctly
\( \frac{1}{20} \)
20
210
6720

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{5!} \)
\( \frac{3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4} \)
\( \frac{1}{20} \)


2

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

absolute value

greatest common factor

least common factor

least common multiple


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


3

What is 3b2 + 2b2?

66% Answer Correctly
-b-2
5b-4
5b2
-b2

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

3b2 + 2b2
(3 + 2)b2
5b2


4

If there were a total of 350 raffle tickets sold and you bought 14 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
6%
4%
10%
1%

Solution

You have 14 out of the total of 350 raffle tickets sold so you have a (\( \frac{14}{350} \)) x 100 = \( \frac{14 \times 100}{350} \) = \( \frac{1400}{350} \) = 4% chance to win the raffle.


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

55% Answer Correctly

distributive property for multiplication

commutative property for division

commutative property for multiplication

distributive property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).