| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.34 |
| Score | 0% | 67% |
Simplify \( \frac{20}{52} \).
| \( \frac{5}{13} \) | |
| \( \frac{5}{18} \) | |
| \( \frac{7}{11} \) | |
| \( \frac{9}{13} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 52 are [1, 2, 4, 13, 26, 52]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{20}{52} \) = \( \frac{\frac{20}{4}}{\frac{52}{4}} \) = \( \frac{5}{13} \)
Monty loaned Latoya $1,300 at an annual interest rate of 2%. If no payments are made, what is the total amount owed at the end of the first year?
| $1,326 | |
| $1,378 | |
| $1,339 | |
| $1,391 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,300
i = 0.02 x $1,300
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $1,300 + $26Diane scored 92% on her final exam. If each question was worth 3 points and there were 180 possible points on the exam, how many questions did Diane answer correctly?
| 40 | |
| 43 | |
| 55 | |
| 47 |
Diane scored 92% on the test meaning she earned 92% of the possible points on the test. There were 180 possible points on the test so she earned 180 x 0.92 = 165 points. Each question is worth 3 points so she got \( \frac{165}{3} \) = 55 questions right.
This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
associative |
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commutative |
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distributive |
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PEDMAS |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
A triathlon course includes a 300m swim, a 50.3km bike ride, and a 11.1km run. What is the total length of the race course?
| 52.6km | |
| 61.7km | |
| 60km | |
| 33.8km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 300 meters to kilometers, divide the distance by 1000 to get 0.3km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.3km + 50.3km + 11.1km
total distance = 61.7km