| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.89 |
| Score | 0% | 58% |
Convert x-5 to remove the negative exponent.
| \( \frac{-5}{x} \) | |
| \( \frac{-5}{-x} \) | |
| \( \frac{1}{x^5} \) | |
| \( \frac{5}{x} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
Solve 3 + (5 + 4) ÷ 4 x 2 - 52
| -17\(\frac{1}{2}\) | |
| 1 | |
| 3 | |
| 1\(\frac{3}{4}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
3 + (5 + 4) ÷ 4 x 2 - 52
P: 3 + (9) ÷ 4 x 2 - 52
E: 3 + 9 ÷ 4 x 2 - 25
MD: 3 + \( \frac{9}{4} \) x 2 - 25
MD: 3 + \( \frac{18}{4} \) - 25
AS: \( \frac{12}{4} \) + \( \frac{18}{4} \) - 25
AS: \( \frac{30}{4} \) - 25
AS: \( \frac{30 - 100}{4} \)
\( \frac{-70}{4} \)
-17\(\frac{1}{2}\)
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 15% off." If Monty buys two shirts, each with a regular price of $37, how much will he pay for both shirts?
| $40.70 | |
| $5.55 | |
| $46.25 | |
| $68.45 |
By buying two shirts, Monty will save $37 x \( \frac{15}{100} \) = \( \frac{$37 x 15}{100} \) = \( \frac{$555}{100} \) = $5.55 on the second shirt.
So, his total cost will be
$37.00 + ($37.00 - $5.55)
$37.00 + $31.45
$68.45
If \( \left|x - 3\right| \) + 0 = 0, which of these is a possible value for x?
| 1 | |
| -5 | |
| 3 | |
| -16 |
First, solve for \( \left|x - 3\right| \):
\( \left|x - 3\right| \) + 0 = 0
\( \left|x - 3\right| \) = 0 + 0
\( \left|x - 3\right| \) = 0
The value inside the absolute value brackets can be either positive or negative so (x - 3) must equal + 0 or -0 for \( \left|x - 3\right| \) to equal 0:
| x - 3 = 0 x = 0 + 3 x = 3 | x - 3 = 0 x = 0 + 3 x = 3 |
So, x = 3 or x = 3.
A circular logo is enlarged to fit the lid of a jar. The new diameter is 65% larger than the original. By what percentage has the area of the logo increased?
| 32\(\frac{1}{2}\)% | |
| 27\(\frac{1}{2}\)% | |
| 25% | |
| 17\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 65% the radius (and, consequently, the total area) increases by \( \frac{65\text{%}}{2} \) = 32\(\frac{1}{2}\)%