ASVAB Arithmetic Reasoning Practice Test 561319 Results

Your Results Global Average
Questions 5 5
Correct 0 3.54
Score 0% 71%

Review

1

Convert x-5 to remove the negative exponent.

67% Answer Correctly
\( \frac{-1}{x^{-5}} \)
\( \frac{1}{x^5} \)
\( \frac{-5}{-x} \)
\( \frac{5}{x} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


2

Frank loaned Roger $1,100 at an annual interest rate of 6%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$24
$77
$49
$66

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,100
i = 0.06 x $1,100
i = $66


3

If there were a total of 400 raffle tickets sold and you bought 16 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
11%
13%
1%
4%

Solution

You have 16 out of the total of 400 raffle tickets sold so you have a (\( \frac{16}{400} \)) x 100 = \( \frac{16 \times 100}{400} \) = \( \frac{1600}{400} \) = 4% chance to win the raffle.


4

A triathlon course includes a 300m swim, a 40.2km bike ride, and a 12.4km run. What is the total length of the race course?

69% Answer Correctly
52.9km
37.6km
64.6km
27.8km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 300 meters to kilometers, divide the distance by 1000 to get 0.3km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.3km + 40.2km + 12.4km
total distance = 52.9km


5

Which of the following is a mixed number?

82% Answer Correctly

\(1 {2 \over 5} \)

\({7 \over 5} \)

\({a \over 5} \)

\({5 \over 7} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.