| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.14 |
| Score | 0% | 63% |
What is \( \frac{3}{3} \) + \( \frac{6}{11} \)?
| \( \frac{6}{9} \) | |
| \( \frac{8}{12} \) | |
| 1\(\frac{6}{11}\) | |
| 1 \( \frac{1}{33} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 11 are [11, 22, 33, 44, 55, 66, 77, 88, 99]. The first few multiples they share are [33, 66, 99] making 33 the smallest multiple 3 and 11 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{3 x 11}{3 x 11} \) + \( \frac{6 x 3}{11 x 3} \)
\( \frac{33}{33} \) + \( \frac{18}{33} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{33 + 18}{33} \) = \( \frac{51}{33} \) = 1\(\frac{6}{11}\)
What is c2 + 4c2?
| 3c2 | |
| 5c4 | |
| -3c2 | |
| 5c2 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
1c2 + 4c2
(1 + 4)c2
5c2
Find the average of the following numbers: 16, 10, 17, 9.
| 16 | |
| 13 | |
| 18 | |
| 8 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{16 + 10 + 17 + 9}{4} \) = \( \frac{52}{4} \) = 13
Simplify \( \sqrt{125} \)
| 4\( \sqrt{5} \) | |
| 5\( \sqrt{5} \) | |
| 2\( \sqrt{5} \) | |
| 8\( \sqrt{5} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{125} \)
\( \sqrt{25 \times 5} \)
\( \sqrt{5^2 \times 5} \)
5\( \sqrt{5} \)
A circular logo is enlarged to fit the lid of a jar. The new diameter is 60% larger than the original. By what percentage has the area of the logo increased?
| 22\(\frac{1}{2}\)% | |
| 37\(\frac{1}{2}\)% | |
| 35% | |
| 30% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 60% the radius (and, consequently, the total area) increases by \( \frac{60\text{%}}{2} \) = 30%