ASVAB Arithmetic Reasoning Practice Test 561456 Results

Your Results Global Average
Questions 5 5
Correct 0 3.14
Score 0% 63%

Review

1

What is \( \frac{3}{3} \) + \( \frac{6}{11} \)?

60% Answer Correctly
\( \frac{6}{9} \)
\( \frac{8}{12} \)
1\(\frac{6}{11}\)
1 \( \frac{1}{33} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 11 are [11, 22, 33, 44, 55, 66, 77, 88, 99]. The first few multiples they share are [33, 66, 99] making 33 the smallest multiple 3 and 11 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{3 x 11}{3 x 11} \) + \( \frac{6 x 3}{11 x 3} \)

\( \frac{33}{33} \) + \( \frac{18}{33} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{33 + 18}{33} \) = \( \frac{51}{33} \) = 1\(\frac{6}{11}\)


2

What is c2 + 4c2?

66% Answer Correctly
3c2
5c4
-3c2
5c2

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

1c2 + 4c2
(1 + 4)c2
5c2


3

Find the average of the following numbers: 16, 10, 17, 9.

75% Answer Correctly
16
13
18
8

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{16 + 10 + 17 + 9}{4} \) = \( \frac{52}{4} \) = 13


4

Simplify \( \sqrt{125} \)

62% Answer Correctly
4\( \sqrt{5} \)
5\( \sqrt{5} \)
2\( \sqrt{5} \)
8\( \sqrt{5} \)

Solution

To simplify a radical, factor out the perfect squares:

\( \sqrt{125} \)
\( \sqrt{25 \times 5} \)
\( \sqrt{5^2 \times 5} \)
5\( \sqrt{5} \)


5

A circular logo is enlarged to fit the lid of a jar. The new diameter is 60% larger than the original. By what percentage has the area of the logo increased?

51% Answer Correctly
22\(\frac{1}{2}\)%
37\(\frac{1}{2}\)%
35%
30%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 60% the radius (and, consequently, the total area) increases by \( \frac{60\text{%}}{2} \) = 30%