| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.93 |
| Score | 0% | 59% |
April scored 83% on her final exam. If each question was worth 4 points and there were 240 possible points on the exam, how many questions did April answer correctly?
| 40 | |
| 36 | |
| 48 | |
| 50 |
April scored 83% on the test meaning she earned 83% of the possible points on the test. There were 240 possible points on the test so she earned 240 x 0.83 = 200 points. Each question is worth 4 points so she got \( \frac{200}{4} \) = 50 questions right.
Simplify \( \sqrt{63} \)
| 3\( \sqrt{14} \) | |
| 3\( \sqrt{7} \) | |
| 2\( \sqrt{7} \) | |
| 5\( \sqrt{7} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{63} \)
\( \sqrt{9 \times 7} \)
\( \sqrt{3^2 \times 7} \)
3\( \sqrt{7} \)
A circular logo is enlarged to fit the lid of a jar. The new diameter is 35% larger than the original. By what percentage has the area of the logo increased?
| 30% | |
| 20% | |
| 17\(\frac{1}{2}\)% | |
| 32\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 35% the radius (and, consequently, the total area) increases by \( \frac{35\text{%}}{2} \) = 17\(\frac{1}{2}\)%
What is 7a6 - 3a6?
| -4a6 | |
| 10a12 | |
| 4a6 | |
| 10a-12 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
7a6 - 3a6
(7 - 3)a6
4a6
How many 2 gallon cans worth of fuel would you need to pour into an empty 8 gallon tank to fill it exactly halfway?
| 5 | |
| 2 | |
| 4 | |
| 7 |
To fill a 8 gallon tank exactly halfway you'll need 4 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{4 \text{ gallons}}{2 \text{ gallons}} \) = 2