| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.61 |
| Score | 0% | 72% |
What is the distance in miles of a trip that takes 2 hours at an average speed of 75 miles per hour?
| 45 miles | |
| 150 miles | |
| 60 miles | |
| 325 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 75mph \times 2h \)
150 miles
If \( \left|c + 3\right| \) + 2 = -3, which of these is a possible value for c?
| 4 | |
| -12 | |
| 2 | |
| 0 |
First, solve for \( \left|c + 3\right| \):
\( \left|c + 3\right| \) + 2 = -3
\( \left|c + 3\right| \) = -3 - 2
\( \left|c + 3\right| \) = -5
The value inside the absolute value brackets can be either positive or negative so (c + 3) must equal - 5 or --5 for \( \left|c + 3\right| \) to equal -5:
| c + 3 = -5 c = -5 - 3 c = -8 | c + 3 = 5 c = 5 - 3 c = 2 |
So, c = 2 or c = -8.
What is the next number in this sequence: 1, 9, 17, 25, 33, __________ ?
| 44 | |
| 41 | |
| 47 | |
| 48 |
The equation for this sequence is:
an = an-1 + 8
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 8
a6 = 33 + 8
a6 = 41
If a rectangle is twice as long as it is wide and has a perimeter of 36 meters, what is the area of the rectangle?
| 128 m2 | |
| 162 m2 | |
| 72 m2 | |
| 2 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 36 meters so the equation becomes: 2w + 2h = 36.
Putting these two equations together and solving for width (w):
2w + 2h = 36
w + h = \( \frac{36}{2} \)
w + h = 18
w = 18 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 18 - 2w
3w = 18
w = \( \frac{18}{3} \)
w = 6
Since h = 2w that makes h = (2 x 6) = 12 and the area = h x w = 6 x 12 = 72 m2
9 members of a bridal party need transported to a wedding reception but there are only 4 2-passenger taxis available to take them. How many will need to find other transportation?
| 8 | |
| 3 | |
| 6 | |
| 1 |
There are 4 2-passenger taxis available so that's 4 x 2 = 8 total seats. There are 9 people needing transportation leaving 9 - 8 = 1 who will have to find other transportation.