| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.21 |
| Score | 0% | 64% |
Solve 2 + (4 + 3) ÷ 4 x 5 - 32
| 1 | |
| 2 | |
| 1\(\frac{3}{4}\) | |
| \(\frac{1}{4}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
2 + (4 + 3) ÷ 4 x 5 - 32
P: 2 + (7) ÷ 4 x 5 - 32
E: 2 + 7 ÷ 4 x 5 - 9
MD: 2 + \( \frac{7}{4} \) x 5 - 9
MD: 2 + \( \frac{35}{4} \) - 9
AS: \( \frac{8}{4} \) + \( \frac{35}{4} \) - 9
AS: \( \frac{43}{4} \) - 9
AS: \( \frac{43 - 36}{4} \)
\( \frac{7}{4} \)
1\(\frac{3}{4}\)
Simplify \( \frac{28}{68} \).
| \( \frac{5}{19} \) | |
| \( \frac{7}{17} \) | |
| \( \frac{3}{7} \) | |
| \( \frac{3}{10} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 68 are [1, 2, 4, 17, 34, 68]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{28}{68} \) = \( \frac{\frac{28}{4}}{\frac{68}{4}} \) = \( \frac{7}{17} \)
How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 25 gallon tank to fill it exactly halfway?
| 8 | |
| 6 | |
| 5 | |
| 9 |
To fill a 25 gallon tank exactly halfway you'll need 12\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:
cans = \( \frac{12\frac{1}{2} \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 5
Which of the following is not a prime number?
2 |
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7 |
|
9 |
|
5 |
A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.
Find the average of the following numbers: 17, 13, 18, 12.
| 15 | |
| 14 | |
| 12 | |
| 11 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{17 + 13 + 18 + 12}{4} \) = \( \frac{60}{4} \) = 15