ASVAB Arithmetic Reasoning Practice Test 569401 Results

Your Results Global Average
Questions 5 5
Correct 0 3.21
Score 0% 64%

Review

1

Solve 2 + (4 + 3) ÷ 4 x 5 - 32

53% Answer Correctly
1
2
1\(\frac{3}{4}\)
\(\frac{1}{4}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (4 + 3) ÷ 4 x 5 - 32
P: 2 + (7) ÷ 4 x 5 - 32
E: 2 + 7 ÷ 4 x 5 - 9
MD: 2 + \( \frac{7}{4} \) x 5 - 9
MD: 2 + \( \frac{35}{4} \) - 9
AS: \( \frac{8}{4} \) + \( \frac{35}{4} \) - 9
AS: \( \frac{43}{4} \) - 9
AS: \( \frac{43 - 36}{4} \)
\( \frac{7}{4} \)
1\(\frac{3}{4}\)


2

Simplify \( \frac{28}{68} \).

77% Answer Correctly
\( \frac{5}{19} \)
\( \frac{7}{17} \)
\( \frac{3}{7} \)
\( \frac{3}{10} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 68 are [1, 2, 4, 17, 34, 68]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{28}{68} \) = \( \frac{\frac{28}{4}}{\frac{68}{4}} \) = \( \frac{7}{17} \)


3

How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 25 gallon tank to fill it exactly halfway?

52% Answer Correctly
8
6
5
9

Solution

To fill a 25 gallon tank exactly halfway you'll need 12\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:

cans = \( \frac{12\frac{1}{2} \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 5


4

Which of the following is not a prime number?

65% Answer Correctly

2

7

9

5


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


5

Find the average of the following numbers: 17, 13, 18, 12.

75% Answer Correctly
15
14
12
11

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{17 + 13 + 18 + 12}{4} \) = \( \frac{60}{4} \) = 15