| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.10 |
| Score | 0% | 62% |
April scored 81% on her final exam. If each question was worth 4 points and there were 360 possible points on the exam, how many questions did April answer correctly?
| 58 | |
| 76 | |
| 88 | |
| 73 |
April scored 81% on the test meaning she earned 81% of the possible points on the test. There were 360 possible points on the test so she earned 360 x 0.81 = 292 points. Each question is worth 4 points so she got \( \frac{292}{4} \) = 73 questions right.
If there were a total of 300 raffle tickets sold and you bought 12 tickets, what's the probability that you'll win the raffle?
| 14% | |
| 1% | |
| 4% | |
| 2% |
You have 12 out of the total of 300 raffle tickets sold so you have a (\( \frac{12}{300} \)) x 100 = \( \frac{12 \times 100}{300} \) = \( \frac{1200}{300} \) = 4% chance to win the raffle.
A tiger in a zoo has consumed 81 pounds of food in 9 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 108 pounds?
| 9 | |
| 1 | |
| 8 | |
| 3 |
If the tiger has consumed 81 pounds of food in 9 days that's \( \frac{81}{9} \) = 9 pounds of food per day. The tiger needs to consume 108 - 81 = 27 more pounds of food to reach 108 pounds total. At 9 pounds of food per day that's \( \frac{27}{9} \) = 3 more days.
In a class of 24 students, 15 are taking German and 7 are taking Spanish. Of the students studying German or Spanish, 7 are taking both courses. How many students are not enrolled in either course?
| 24 | |
| 18 | |
| 9 | |
| 13 |
The number of students taking German or Spanish is 15 + 7 = 22. Of that group of 22, 7 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 22 - 7 = 15 who are taking at least one language. 24 - 15 = 9 students who are not taking either language.
What is \( \frac{1}{9} \) x \( \frac{4}{7} \)?
| \(\frac{1}{14}\) | |
| \(\frac{1}{54}\) | |
| \(\frac{6}{35}\) | |
| \(\frac{4}{63}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{9} \) x \( \frac{4}{7} \) = \( \frac{1 x 4}{9 x 7} \) = \( \frac{4}{63} \) = \(\frac{4}{63}\)