| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.99 |
| Score | 0% | 60% |
A bread recipe calls for 2\(\frac{1}{8}\) cups of flour. If you only have \(\frac{1}{2}\) cup, how much more flour is needed?
| 1 cups | |
| 2\(\frac{1}{8}\) cups | |
| 2 cups | |
| 1\(\frac{5}{8}\) cups |
The amount of flour you need is (2\(\frac{1}{8}\) - \(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{17}{8} \) - \( \frac{4}{8} \)) cups
\( \frac{13}{8} \) cups
1\(\frac{5}{8}\) cups
Alex loaned Bob $1,400 at an annual interest rate of 2%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $18 | |
| $13 | |
| $28 | |
| $48 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,400
i = 0.02 x $1,400
i = $28
A tiger in a zoo has consumed 96 pounds of food in 12 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 120 pounds?
| 12 | |
| 15 | |
| 3 | |
| 6 |
If the tiger has consumed 96 pounds of food in 12 days that's \( \frac{96}{12} \) = 8 pounds of food per day. The tiger needs to consume 120 - 96 = 24 more pounds of food to reach 120 pounds total. At 8 pounds of food per day that's \( \frac{24}{8} \) = 3 more days.
Solve 2 + (5 + 3) ÷ 3 x 4 - 42
| \(\frac{3}{7}\) | |
| -3\(\frac{1}{3}\) | |
| \(\frac{3}{5}\) | |
| \(\frac{2}{7}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
2 + (5 + 3) ÷ 3 x 4 - 42
P: 2 + (8) ÷ 3 x 4 - 42
E: 2 + 8 ÷ 3 x 4 - 16
MD: 2 + \( \frac{8}{3} \) x 4 - 16
MD: 2 + \( \frac{32}{3} \) - 16
AS: \( \frac{6}{3} \) + \( \frac{32}{3} \) - 16
AS: \( \frac{38}{3} \) - 16
AS: \( \frac{38 - 48}{3} \)
\( \frac{-10}{3} \)
-3\(\frac{1}{3}\)
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for division |
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commutative property for multiplication |
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distributive property for division |
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distributive property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).