| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.51 |
| Score | 0% | 70% |
What is -6z2 x 5z5?
| -30z3 | |
| -z7 | |
| -30z7 | |
| -30z10 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-6z2 x 5z5
(-6 x 5)z(2 + 5)
-30z7
What is (x3)2?
| x | |
| 2x3 | |
| 3x2 | |
| x6 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(x3)2Find the average of the following numbers: 13, 11, 14, 10.
| 12 | |
| 7 | |
| 16 | |
| 14 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{13 + 11 + 14 + 10}{4} \) = \( \frac{48}{4} \) = 12
Convert 4,206,000 to scientific notation.
| 4.206 x 105 | |
| 4.206 x 10-5 | |
| 4.206 x 106 | |
| 4.206 x 10-6 |
A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:
4,206,000 in scientific notation is 4.206 x 106
What is \( \frac{8}{9} \) - \( \frac{3}{15} \)?
| \( \frac{7}{45} \) | |
| 1 \( \frac{1}{10} \) | |
| \(\frac{31}{45}\) | |
| \( \frac{6}{9} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90] and the first few multiples of 15 are [15, 30, 45, 60, 75, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 9 and 15 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{8 x 5}{9 x 5} \) - \( \frac{3 x 3}{15 x 3} \)
\( \frac{40}{45} \) - \( \frac{9}{45} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{40 - 9}{45} \) = \( \frac{31}{45} \) = \(\frac{31}{45}\)