If the tiger has consumed 90 pounds of food in 9 days that's \( \frac{90}{9} \) = 10 pounds of food per day. The tiger needs to consume 120 - 90 = 30 more pounds of food to reach 120 pounds total. At 10 pounds of food per day that's \( \frac{30}{10} \) = 3 more days.

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $600
i = 0.03 x $600

No payments were made so the total amount due is the original amount + the accumulated interest:

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{x^5}{5x^2} \)
\( \frac{1}{5} \) x^{(5 - 2)}
\(\frac{1}{5}\)x³

If a single cook can bake 3 large cakes per hour and the kitchen is available for 2 hours, a single cook can bake 3 x 2 = 6 large cakes during that time. 39 large cakes are needed for the party so \( \frac{39}{6} \) = 6\(\frac{1}{2}\) cooks are needed to bake the required number of large cakes.

If a single cook can bake 10 small cakes per hour and the kitchen is available for 2 hours, a single cook can bake 10 x 2 = 20 small cakes during that time. 160 small cakes are needed for the party so \( \frac{160}{20} \) = 8 cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 7 + 8 = 15 cooks.

To fill a 15 gallon tank exactly halfway you'll need 7\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:

cans = \( \frac{7\frac{1}{2} \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 5