ASVAB Arithmetic Reasoning Practice Test 581638 Results

Your Results Global Average
Questions 5 5
Correct 0 3.33
Score 0% 67%

Review

1

Which of the following is an improper fraction?

70% Answer Correctly

\(1 {2 \over 5} \)

\({7 \over 5} \)

\({a \over 5} \)

\({2 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


2

Solve for \( \frac{5!}{2!} \)

67% Answer Correctly
72
60
8
\( \frac{1}{210} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{5!}{2!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{5 \times 4 \times 3}{1} \)
\( 5 \times 4 \times 3 \)
60


3

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

absolute value

least common factor

least common multiple

greatest common factor


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


4

What is \( \frac{-9b^6}{2b^4} \)?

60% Answer Correctly
-4\(\frac{1}{2}\)b\(\frac{2}{3}\)
-\(\frac{2}{9}\)b-2
-4\(\frac{1}{2}\)b-2
-4\(\frac{1}{2}\)b2

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-9b^6}{2b^4} \)
\( \frac{-9}{2} \) b(6 - 4)
-4\(\frac{1}{2}\)b2


5

How many 6-passenger vans will it take to drive all 96 members of the football team to an away game?

81% Answer Correctly
11 vans
9 vans
16 vans
3 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{96}{6} \) = 16