| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.16 |
| Score | 0% | 63% |
12 members of a bridal party need transported to a wedding reception but there are only 2 5-passenger taxis available to take them. How many will need to find other transportation?
| 8 | |
| 2 | |
| 7 | |
| 3 |
There are 2 5-passenger taxis available so that's 2 x 5 = 10 total seats. There are 12 people needing transportation leaving 12 - 10 = 2 who will have to find other transportation.
How many hours does it take a car to travel 150 miles at an average speed of 30 miles per hour?
| 2 hours | |
| 8 hours | |
| 5 hours | |
| 1 hour |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{150mi}{30mph} \)
5 hours
Which of the following statements about exponents is false?
b1 = 1 |
|
b1 = b |
|
all of these are false |
|
b0 = 1 |
A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).
How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 6 gallon tank to fill it exactly halfway?
| 2 | |
| 5 | |
| 4 | |
| 2 |
To fill a 6 gallon tank exactly halfway you'll need 3 gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:
cans = \( \frac{3 \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 2
What is \( \frac{4}{4} \) - \( \frac{3}{12} \)?
| 1 \( \frac{5}{12} \) | |
| 1 \( \frac{8}{14} \) | |
| 2 \( \frac{4}{11} \) | |
| \(\frac{3}{4}\) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 12 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{4 x 3}{4 x 3} \) - \( \frac{3 x 1}{12 x 1} \)
\( \frac{12}{12} \) - \( \frac{3}{12} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{12 - 3}{12} \) = \( \frac{9}{12} \) = \(\frac{3}{4}\)