ASVAB Arithmetic Reasoning Practice Test 583004 Results

	Your Results	Global Average
Questions	5	5
Correct	0	2.76
Score	0%	55%

Review

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 25% off." If Alex buys two shirts, each with a regular price of $44, how much will he pay for both shirts?

57% Answer Correctly

	$77.00
	$50.60
	$46.20
	$11.00

Solution

By buying two shirts, Alex will save $44 x $ \frac{25}{100} $ = $ \frac{$44 x 25}{100} $ = $ \frac{$1100}{100} $ = $11.00 on the second shirt.

So, his total cost will be
$44.00 + ($44.00 - $11.00)
$44.00 + $33.00
$77.00

What is $ 5 $$ \sqrt{18} $ - $ 9 $$ \sqrt{2} $

39% Answer Correctly

	45$ \sqrt{36} $
	-4$ \sqrt{9} $
	6$ \sqrt{2} $
	45$ \sqrt{18} $

Solution

To subtract these radicals together their radicands must be the same:

5$ \sqrt{18} $ - 9$ \sqrt{2} $
5$ \sqrt{9 \times 2} $ - 9$ \sqrt{2} $
5$ \sqrt{3^2 \times 2} $ - 9$ \sqrt{2} $
(5)(3)$ \sqrt{2} $ - 9$ \sqrt{2} $
15$ \sqrt{2} $ - 9$ \sqrt{2} $

Now that the radicands are identical, you can subtract them:

15$ \sqrt{2} $ - 9$ \sqrt{2} $
(15 - 9)$ \sqrt{2} $
6$ \sqrt{2} $

What is $ \frac{3z^8}{5z^3} $?

60% Answer Correctly

	$\frac{3}{5}$z¹¹
	$\frac{3}{5}$z⁵
	$\frac{3}{5}$z²⁴
	1$\frac{2}{3}$z¹¹

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

$ \frac{3z^8}{5z^3} $
$ \frac{3}{5} $ z^{(8 - 3)}
$\frac{3}{5}$z⁵

Cooks are needed to prepare for a large party. Each cook can bake either 3 large cakes or 13 small cakes per hour. The kitchen is available for 2 hours and 40 large cakes and 410 small cakes need to be baked.

How many cooks are required to bake the required number of cakes during the time the kitchen is available?

41% Answer Correctly

	12
	23
	14
	15

Solution

If a single cook can bake 3 large cakes per hour and the kitchen is available for 2 hours, a single cook can bake 3 x 2 = 6 large cakes during that time. 40 large cakes are needed for the party so $ \frac{40}{6} $ = 6$\frac{2}{3}$ cooks are needed to bake the required number of large cakes.

If a single cook can bake 13 small cakes per hour and the kitchen is available for 2 hours, a single cook can bake 13 x 2 = 26 small cakes during that time. 410 small cakes are needed for the party so $ \frac{410}{26} $ = 15$\frac{10}{13}$ cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 7 + 16 = 23 cooks.

Simplify $ \frac{20}{44} $.

77% Answer Correctly

	$ \frac{7}{12} $
	$ \frac{2}{9} $
	$ \frac{5}{11} $
	$ \frac{10}{13} $

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 44 are [1, 2, 4, 11, 22, 44]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

$ \frac{20}{44} $ = $ \frac{\frac{20}{4}}{\frac{44}{4}} $ = $ \frac{5}{11} $

	45\( \sqrt{36} \)
	-4\( \sqrt{9} \)
	6\( \sqrt{2} \)
	45\( \sqrt{18} \)

	\(\frac{3}{5}\)z¹¹
	\(\frac{3}{5}\)z⁵
	\(\frac{3}{5}\)z²⁴
	1\(\frac{2}{3}\)z¹¹

	\( \frac{7}{12} \)
	\( \frac{2}{9} \)
	\( \frac{5}{11} \)
	\( \frac{10}{13} \)