| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.30 |
| Score | 0% | 66% |
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 20% off." If Roger buys two shirts, each with a regular price of $26, how much money will he save?
| $5.20 | |
| $9.10 | |
| $1.30 | |
| $2.60 |
By buying two shirts, Roger will save $26 x \( \frac{20}{100} \) = \( \frac{$26 x 20}{100} \) = \( \frac{$520}{100} \) = $5.20 on the second shirt.
The total water usage for a city is 25,000 gallons each day. Of that total, 24% is for personal use and 34% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 2,500 | |
| 13,000 | |
| 12,000 | |
| 12,250 |
34% of the water consumption is industrial use and 24% is personal use so (34% - 24%) = 10% more water is used for industrial purposes. 25,000 gallons are consumed daily so industry consumes \( \frac{10}{100} \) x 25,000 gallons = 2,500 gallons.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for division |
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distributive property for multiplication |
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commutative property for multiplication |
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distributive property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
If a car travels 240 miles in 4 hours, what is the average speed?
| 70 mph | |
| 45 mph | |
| 60 mph | |
| 40 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)What is \( \frac{-8a^5}{9a^4} \)?
| -\(\frac{8}{9}\)a-1 | |
| -\(\frac{8}{9}\)a\(\frac{4}{5}\) | |
| -\(\frac{8}{9}\)a9 | |
| -\(\frac{8}{9}\)a |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-8a^5}{9a^4} \)
\( \frac{-8}{9} \) a(5 - 4)
-\(\frac{8}{9}\)a