| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.31 |
| Score | 0% | 66% |
If a car travels 90 miles in 6 hours, what is the average speed?
| 35 mph | |
| 30 mph | |
| 15 mph | |
| 60 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)If the ratio of home fans to visiting fans in a crowd is 2:1 and all 38,000 seats in a stadium are filled, how many home fans are in attendance?
| 39,167 | |
| 25,333 | |
| 37,500 | |
| 26,667 |
A ratio of 2:1 means that there are 2 home fans for every one visiting fan. So, of every 3 fans, 2 are home fans and \( \frac{2}{3} \) of every fan in the stadium is a home fan:
38,000 fans x \( \frac{2}{3} \) = \( \frac{76000}{3} \) = 25,333 fans.
A triathlon course includes a 200m swim, a 40.6km bike ride, and a 7.1km run. What is the total length of the race course?
| 54.2km | |
| 47.9km | |
| 33.2km | |
| 62.9km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 200 meters to kilometers, divide the distance by 1000 to get 0.2km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.2km + 40.6km + 7.1km
total distance = 47.9km
What is the distance in miles of a trip that takes 9 hours at an average speed of 55 miles per hour?
| 200 miles | |
| 495 miles | |
| 630 miles | |
| 150 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 55mph \times 9h \)
495 miles
Cooks are needed to prepare for a large party. Each cook can bake either 2 large cakes or 16 small cakes per hour. The kitchen is available for 2 hours and 30 large cakes and 190 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 98 | |
| 14 | |
| 15 | |
| 7 |
If a single cook can bake 2 large cakes per hour and the kitchen is available for 2 hours, a single cook can bake 2 x 2 = 4 large cakes during that time. 30 large cakes are needed for the party so \( \frac{30}{4} \) = 7\(\frac{1}{2}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 16 small cakes per hour and the kitchen is available for 2 hours, a single cook can bake 16 x 2 = 32 small cakes during that time. 190 small cakes are needed for the party so \( \frac{190}{32} \) = 5\(\frac{15}{16}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 8 + 6 = 14 cooks.