ASVAB Arithmetic Reasoning Practice Test 588489 Results

Your Results Global Average
Questions 5 5
Correct 0 3.56
Score 0% 71%

Review

1

How many 6-passenger vans will it take to drive all 30 members of the football team to an away game?

80% Answer Correctly
5 vans
4 vans
11 vans
14 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{30}{6} \) = 5


2

What is the next number in this sequence: 1, 6, 11, 16, 21, __________ ?

92% Answer Correctly
35
34
26
31

Solution

The equation for this sequence is:

an = an-1 + 5

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 5
a6 = 21 + 5
a6 = 26


3

If \( \left|a + 3\right| \) + 1 = -8, which of these is a possible value for a?

62% Answer Correctly
-7
7
6
10

Solution

First, solve for \( \left|a + 3\right| \):

\( \left|a + 3\right| \) + 1 = -8
\( \left|a + 3\right| \) = -8 - 1
\( \left|a + 3\right| \) = -9

The value inside the absolute value brackets can be either positive or negative so (a + 3) must equal - 9 or --9 for \( \left|a + 3\right| \) to equal -9:

a + 3 = -9
a = -9 - 3
a = -12
a + 3 = 9
a = 9 - 3
a = 6

So, a = 6 or a = -12.


4

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 50% off." If Charlie buys two shirts, each with a regular price of $20, how much will he pay for both shirts?

57% Answer Correctly
$26.00
$29.00
$10.00
$30.00

Solution

By buying two shirts, Charlie will save $20 x \( \frac{50}{100} \) = \( \frac{$20 x 50}{100} \) = \( \frac{$1000}{100} \) = $10.00 on the second shirt.

So, his total cost will be
$20.00 + ($20.00 - $10.00)
$20.00 + $10.00
$30.00


5

Solve for \( \frac{2!}{4!} \)

66% Answer Correctly
30
\( \frac{1}{20} \)
\( \frac{1}{12} \)
56

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{2!}{4!} \)
\( \frac{2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4 \times 3} \)
\( \frac{1}{12} \)