| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.09 |
| Score | 0% | 62% |
What is \( \frac{6a^9}{7a^4} \)?
| \(\frac{6}{7}\)a2\(\frac{1}{4}\) | |
| 1\(\frac{1}{6}\)a13 | |
| \(\frac{6}{7}\)a36 | |
| \(\frac{6}{7}\)a5 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{6a^9}{7a^4} \)
\( \frac{6}{7} \) a(9 - 4)
\(\frac{6}{7}\)a5
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 40% off." If Alex buys two shirts, each with a regular price of $21, how much will he pay for both shirts?
| $22.05 | |
| $29.40 | |
| $33.60 | |
| $8.40 |
By buying two shirts, Alex will save $21 x \( \frac{40}{100} \) = \( \frac{$21 x 40}{100} \) = \( \frac{$840}{100} \) = $8.40 on the second shirt.
So, his total cost will be
$21.00 + ($21.00 - $8.40)
$21.00 + $12.60
$33.60
The __________ is the greatest factor that divides two integers.
greatest common multiple |
|
least common multiple |
|
greatest common factor |
|
absolute value |
The greatest common factor (GCF) is the greatest factor that divides two integers.
Monty loaned Betty $300 at an annual interest rate of 1%. If no payments are made, what is the total amount owed at the end of the first year?
| $309 | |
| $303 | |
| $321 | |
| $315 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $300
i = 0.01 x $300
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $300 + $3If all of a roofing company's 16 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?
| 7 | |
| 8 | |
| 12 | |
| 6 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 16 workers at the company now and that's enough to staff 4 crews so there are \( \frac{16}{4} \) = 4 workers on a crew. 6 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 6 x 4 = 24 total workers to staff the crews during the busy season. The company already employs 16 workers so they need to add 24 - 16 = 8 new staff for the busy season.