ASVAB Arithmetic Reasoning Practice Test 58906 Results

Your Results Global Average
Questions 5 5
Correct 0 2.93
Score 0% 59%

Review

1

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

absolute value

least common multiple

least common factor

greatest common factor


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


2

What is \( \sqrt{\frac{36}{36}} \)?

70% Answer Correctly
\(\frac{7}{8}\)
\(\frac{2}{3}\)
\(\frac{4}{7}\)
1

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{36}{36}} \)
\( \frac{\sqrt{36}}{\sqrt{36}} \)
\( \frac{\sqrt{6^2}}{\sqrt{6^2}} \)
1


3

What is \( 4 \)\( \sqrt{48} \) - \( 6 \)\( \sqrt{3} \)

38% Answer Correctly
24\( \sqrt{144} \)
10\( \sqrt{3} \)
-2\( \sqrt{-7} \)
-2\( \sqrt{3} \)

Solution

To subtract these radicals together their radicands must be the same:

4\( \sqrt{48} \) - 6\( \sqrt{3} \)
4\( \sqrt{16 \times 3} \) - 6\( \sqrt{3} \)
4\( \sqrt{4^2 \times 3} \) - 6\( \sqrt{3} \)
(4)(4)\( \sqrt{3} \) - 6\( \sqrt{3} \)
16\( \sqrt{3} \) - 6\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

16\( \sqrt{3} \) - 6\( \sqrt{3} \)
(16 - 6)\( \sqrt{3} \)
10\( \sqrt{3} \)


4

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

55% Answer Correctly

commutative property for division

distributive property for multiplication

distributive property for division

commutative property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


5

What is \( \frac{3}{7} \) x \( \frac{4}{8} \)?

72% Answer Correctly
\(\frac{2}{15}\)
\(\frac{1}{9}\)
1\(\frac{1}{2}\)
\(\frac{3}{14}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{7} \) x \( \frac{4}{8} \) = \( \frac{3 x 4}{7 x 8} \) = \( \frac{12}{56} \) = \(\frac{3}{14}\)