ASVAB Arithmetic Reasoning Practice Test 589224 Results

Your Results Global Average
Questions 5 5
Correct 0 3.37
Score 0% 67%

Review

1

What is \( 6 \)\( \sqrt{80} \) - \( 4 \)\( \sqrt{5} \)

39% Answer Correctly
2\( \sqrt{16} \)
2\( \sqrt{5} \)
20\( \sqrt{5} \)
24\( \sqrt{5} \)

Solution

To subtract these radicals together their radicands must be the same:

6\( \sqrt{80} \) - 4\( \sqrt{5} \)
6\( \sqrt{16 \times 5} \) - 4\( \sqrt{5} \)
6\( \sqrt{4^2 \times 5} \) - 4\( \sqrt{5} \)
(6)(4)\( \sqrt{5} \) - 4\( \sqrt{5} \)
24\( \sqrt{5} \) - 4\( \sqrt{5} \)

Now that the radicands are identical, you can subtract them:

24\( \sqrt{5} \) - 4\( \sqrt{5} \)
(24 - 4)\( \sqrt{5} \)
20\( \sqrt{5} \)


2

Which of the following is an improper fraction?

70% Answer Correctly

\(1 {2 \over 5} \)

\({a \over 5} \)

\({2 \over 5} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


3

What is the next number in this sequence: 1, 9, 17, 25, 33, __________ ?

92% Answer Correctly
35
41
34
45

Solution

The equation for this sequence is:

an = an-1 + 8

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 8
a6 = 33 + 8
a6 = 41


4

Bob loaned Monty $700 at an annual interest rate of 9%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$9
$63
$24
$6

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $700
i = 0.09 x $700
i = $63


5

If \( \left|x + 5\right| \) - 1 = 5, which of these is a possible value for x?

62% Answer Correctly
-13
-17
-4
-11

Solution

First, solve for \( \left|x + 5\right| \):

\( \left|x + 5\right| \) - 1 = 5
\( \left|x + 5\right| \) = 5 + 1
\( \left|x + 5\right| \) = 6

The value inside the absolute value brackets can be either positive or negative so (x + 5) must equal + 6 or -6 for \( \left|x + 5\right| \) to equal 6:

x + 5 = 6
x = 6 - 5
x = 1
x + 5 = -6
x = -6 - 5
x = -11

So, x = -11 or x = 1.