ASVAB Arithmetic Reasoning Practice Test 589314 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.48
Score	0%	70%

Review

Ezra loaned Bob $200 at an annual interest rate of 8%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly

	$15
	$16
	$11
	$72

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = ($ \frac{6}{100} $) x $200
i = 0.08 x $200
i = $16

Find the average of the following numbers: 18, 10, 17, 11.

74% Answer Correctly

	13
	14
	12
	16

Solution

To find the average of these 4 numbers add them together then divide by 4:

$ \frac{18 + 10 + 17 + 11}{4} $ = $ \frac{56}{4} $ = 14

What is $ \frac{6c^7}{9c^4} $?

60% Answer Correctly

	$\frac{2}{3}$c^{1$\frac{3}{4}$}
	$\frac{2}{3}$c²⁸
	$\frac{2}{3}$c³
	1$\frac{1}{2}$c^-3

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

$ \frac{6c^7}{9c^4} $
$ \frac{6}{9} $ c^{(7 - 4)}
$\frac{2}{3}$c³

A bread recipe calls for 2$\frac{3}{8}$ cups of flour. If you only have $\frac{7}{8}$ cup, how much more flour is needed?

62% Answer Correctly

	$\frac{3}{8}$ cups
	2$\frac{3}{4}$ cups
	1$\frac{1}{2}$ cups
	2$\frac{1}{8}$ cups

Solution

The amount of flour you need is (2$\frac{3}{8}$ - $\frac{7}{8}$) cups. Rewrite the quantities so they share a common denominator and subtract:

($ \frac{19}{8} $ - $ \frac{7}{8} $) cups
$ \frac{12}{8} $ cups
1$\frac{1}{2}$ cups

Simplify $ \frac{16}{72} $.

77% Answer Correctly

	$ \frac{2}{9} $
	$ \frac{8}{13} $
	$ \frac{7}{12} $
	$ \frac{5}{13} $

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 16 are [1, 2, 4, 8, 16] and the factors of 72 are [1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72]. They share 4 factors [1, 2, 4, 8] making 8 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

$ \frac{16}{72} $ = $ \frac{\frac{16}{8}}{\frac{72}{8}} $ = $ \frac{2}{9} $

	\(\frac{2}{3}\)c^{1\(\frac{3}{4}\)}
	\(\frac{2}{3}\)c²⁸
	\(\frac{2}{3}\)c³
	1\(\frac{1}{2}\)c^-3

	\(\frac{3}{8}\) cups
	2\(\frac{3}{4}\) cups
	1\(\frac{1}{2}\) cups
	2\(\frac{1}{8}\) cups

	\( \frac{2}{9} \)
	\( \frac{8}{13} \)
	\( \frac{7}{12} \)
	\( \frac{5}{13} \)