The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).

The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40]. The first few multiples they share are [4, 8, 12, 16, 20] making 4 the smallest multiple 2 and 4 have in common.

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{9} \) x \( \frac{3}{5} \) = \( \frac{2 x 3}{9 x 5} \) = \( \frac{6}{45} \) = \(\frac{2}{15}\)

To subtract these radicals together their radicands must be the same:

5\( \sqrt{48} \) - 5\( \sqrt{3} \)
5\( \sqrt{16 \times 3} \) - 5\( \sqrt{3} \)
5\( \sqrt{4^2 \times 3} \) - 5\( \sqrt{3} \)
(5)(4)\( \sqrt{3} \) - 5\( \sqrt{3} \)
20\( \sqrt{3} \) - 5\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).