ASVAB Arithmetic Reasoning Practice Test 592804 Results

Your Results Global Average
Questions 5 5
Correct 0 3.16
Score 0% 63%

Review

1

In a class of 26 students, 15 are taking German and 6 are taking Spanish. Of the students studying German or Spanish, 3 are taking both courses. How many students are not enrolled in either course?

63% Answer Correctly
24
14
8
10

Solution

The number of students taking German or Spanish is 15 + 6 = 21. Of that group of 21, 3 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 21 - 3 = 18 who are taking at least one language. 26 - 18 = 8 students who are not taking either language.


2

What is \( \frac{2}{6} \) x \( \frac{3}{8} \)?

72% Answer Correctly
\(\frac{1}{36}\)
\(\frac{16}{63}\)
\(\frac{1}{8}\)
\(\frac{4}{81}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{6} \) x \( \frac{3}{8} \) = \( \frac{2 x 3}{6 x 8} \) = \( \frac{6}{48} \) = \(\frac{1}{8}\)


3

A tiger in a zoo has consumed 42 pounds of food in 3 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 140 pounds?

56% Answer Correctly
3
7
8
1

Solution

If the tiger has consumed 42 pounds of food in 3 days that's \( \frac{42}{3} \) = 14 pounds of food per day. The tiger needs to consume 140 - 42 = 98 more pounds of food to reach 140 pounds total. At 14 pounds of food per day that's \( \frac{98}{14} \) = 7 more days.


4

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

least common factor

absolute value

least common multiple

greatest common factor


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


5

What is the next number in this sequence: 1, 5, 13, 25, 41, __________ ?

69% Answer Correctly
55
68
64
61

Solution

The equation for this sequence is:

an = an-1 + 4(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 4(6 - 1)
a6 = 41 + 4(5)
a6 = 61