ASVAB Arithmetic Reasoning Practice Test 594228 Results

Your Results Global Average
Questions 5 5
Correct 0 3.43
Score 0% 69%

Review

1

8 members of a bridal party need transported to a wedding reception but there are only 2 3-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
1
7
6
2

Solution

There are 2 3-passenger taxis available so that's 2 x 3 = 6 total seats. There are 8 people needing transportation leaving 8 - 6 = 2 who will have to find other transportation.


2

What is 7y3 - 5y3?

71% Answer Correctly
2y-3
2y3
12y9
12y3

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

7y3 - 5y3
(7 - 5)y3
2y3


3

The __________ is the smallest positive integer that is a multiple of two or more integers.

56% Answer Correctly

least common multiple

absolute value

greatest common factor

least common factor


Solution

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.


4

What is the distance in miles of a trip that takes 3 hours at an average speed of 40 miles per hour?

87% Answer Correctly
140 miles
90 miles
420 miles
120 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 40mph \times 3h \)
120 miles


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

distributive property for multiplication

distributive property for division

commutative property for multiplication

commutative property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).