ASVAB Arithmetic Reasoning Practice Test 59475 Results

Your Results Global Average
Questions 5 5
Correct 0 3.32
Score 0% 66%

Review

1

Solve for \( \frac{6!}{4!} \)

67% Answer Correctly
840
30
7
504

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{6!}{4!} \)
\( \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{6 \times 5}{1} \)
\( 6 \times 5 \)
30


2

What is \( 8 \)\( \sqrt{32} \) + \( 6 \)\( \sqrt{2} \)

35% Answer Correctly
48\( \sqrt{16} \)
38\( \sqrt{2} \)
14\( \sqrt{32} \)
14\( \sqrt{2} \)

Solution

To add these radicals together their radicands must be the same:

8\( \sqrt{32} \) + 6\( \sqrt{2} \)
8\( \sqrt{16 \times 2} \) + 6\( \sqrt{2} \)
8\( \sqrt{4^2 \times 2} \) + 6\( \sqrt{2} \)
(8)(4)\( \sqrt{2} \) + 6\( \sqrt{2} \)
32\( \sqrt{2} \) + 6\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

32\( \sqrt{2} \) + 6\( \sqrt{2} \)
(32 + 6)\( \sqrt{2} \)
38\( \sqrt{2} \)


3

What is \( \sqrt{\frac{81}{16}} \)?

70% Answer Correctly
4\(\frac{1}{2}\)
2
1\(\frac{1}{2}\)
2\(\frac{1}{4}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{81}{16}} \)
\( \frac{\sqrt{81}}{\sqrt{16}} \)
\( \frac{\sqrt{9^2}}{\sqrt{4^2}} \)
\( \frac{9}{4} \)
2\(\frac{1}{4}\)


4

Which of the following is not an integer?

77% Answer Correctly

0

\({1 \over 2}\)

-1

1


Solution

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.


5

How many 14-passenger vans will it take to drive all 95 members of the football team to an away game?

81% Answer Correctly
6 vans
7 vans
5 vans
9 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{95}{14} \) = 6\(\frac{11}{14}\)

So, it will take 6 full vans and one partially full van to transport the entire team making a total of 7 vans.