| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.14 |
| Score | 0% | 63% |
A triathlon course includes a 100m swim, a 50.1km bike ride, and a 11.6km run. What is the total length of the race course?
| 61.8km | |
| 37.2km | |
| 49.6km | |
| 33.8km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.1km + 50.1km + 11.6km
total distance = 61.8km
What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?
| 24 | |
| 32 | |
| 35 | |
| 31 |
The equation for this sequence is:
an = an-1 + 2(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31
If a rectangle is twice as long as it is wide and has a perimeter of 54 meters, what is the area of the rectangle?
| 162 m2 | |
| 18 m2 | |
| 72 m2 | |
| 98 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 54 meters so the equation becomes: 2w + 2h = 54.
Putting these two equations together and solving for width (w):
2w + 2h = 54
w + h = \( \frac{54}{2} \)
w + h = 27
w = 27 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 27 - 2w
3w = 27
w = \( \frac{27}{3} \)
w = 9
Since h = 2w that makes h = (2 x 9) = 18 and the area = h x w = 9 x 18 = 162 m2
A machine in a factory has an error rate of 5 parts per 100. The machine normally runs 24 hours a day and produces 8 parts per hour. Yesterday the machine was shut down for 8 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 121.6 | |
| 145.5 | |
| 115.4 | |
| 96.6 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{5}{100} \) x 8 = \( \frac{5 \times 8}{100} \) = \( \frac{40}{100} \) = 0.4 errors per hour
So, in an average hour, the machine will produce 8 - 0.4 = 7.6 error free parts.
The machine ran for 24 - 8 = 16 hours yesterday so you would expect that 16 x 7.6 = 121.6 error free parts were produced yesterday.
What is (a2)4?
| a8 | |
| 4a2 | |
| a-2 | |
| a6 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(a2)4