| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.49 |
| Score | 0% | 70% |
The total water usage for a city is 25,000 gallons each day. Of that total, 32% is for personal use and 47% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 650 | |
| 3,750 | |
| 3,300 | |
| 10,500 |
47% of the water consumption is industrial use and 32% is personal use so (47% - 32%) = 15% more water is used for industrial purposes. 25,000 gallons are consumed daily so industry consumes \( \frac{15}{100} \) x 25,000 gallons = 3,750 gallons.
How many 13-passenger vans will it take to drive all 76 members of the football team to an away game?
| 5 vans | |
| 6 vans | |
| 3 vans | |
| 4 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{76}{13} \) = 5\(\frac{11}{13}\)
So, it will take 5 full vans and one partially full van to transport the entire team making a total of 6 vans.
What is \( \frac{4}{6} \) x \( \frac{2}{9} \)?
| \(\frac{4}{27}\) | |
| \(\frac{8}{9}\) | |
| \(\frac{1}{12}\) | |
| 1\(\frac{1}{3}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{6} \) x \( \frac{2}{9} \) = \( \frac{4 x 2}{6 x 9} \) = \( \frac{8}{54} \) = \(\frac{4}{27}\)
What is \( \frac{2}{6} \) ÷ \( \frac{3}{5} \)?
| \(\frac{1}{10}\) | |
| \(\frac{1}{5}\) | |
| \(\frac{5}{9}\) | |
| 1\(\frac{2}{3}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{2}{6} \) ÷ \( \frac{3}{5} \) = \( \frac{2}{6} \) x \( \frac{5}{3} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{6} \) x \( \frac{5}{3} \) = \( \frac{2 x 5}{6 x 3} \) = \( \frac{10}{18} \) = \(\frac{5}{9}\)
What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?
| 37 | |
| 39 | |
| 41 | |
| 46 |
The equation for this sequence is:
an = an-1 + 3(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46