| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
Ezra loaned Latoya $1,000 at an annual interest rate of 9%. If no payments are made, what is the total amount owed at the end of the first year?
| $1,010 | |
| $1,090 | |
| $1,040 | |
| $1,050 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,000
i = 0.09 x $1,000
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $1,000 + $90What is \( \frac{-1x^8}{6x^2} \)?
| -\(\frac{1}{6}\)x10 | |
| -6x10 | |
| -\(\frac{1}{6}\)x16 | |
| -\(\frac{1}{6}\)x6 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-x^8}{6x^2} \)
\( \frac{-1}{6} \) x(8 - 2)
-\(\frac{1}{6}\)x6
What is \( \frac{7}{9} \) + \( \frac{4}{15} \)?
| 1\(\frac{2}{45}\) | |
| \( \frac{3}{11} \) | |
| 1 \( \frac{4}{45} \) | |
| 2 \( \frac{5}{13} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90] and the first few multiples of 15 are [15, 30, 45, 60, 75, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 9 and 15 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{7 x 5}{9 x 5} \) + \( \frac{4 x 3}{15 x 3} \)
\( \frac{35}{45} \) + \( \frac{12}{45} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{35 + 12}{45} \) = \( \frac{47}{45} \) = 1\(\frac{2}{45}\)
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 25% off." If Monty buys two shirts, each with a regular price of $45, how much will he pay for both shirts?
| $78.75 | |
| $11.25 | |
| $60.75 | |
| $63.00 |
By buying two shirts, Monty will save $45 x \( \frac{25}{100} \) = \( \frac{$45 x 25}{100} \) = \( \frac{$1125}{100} \) = $11.25 on the second shirt.
So, his total cost will be
$45.00 + ($45.00 - $11.25)
$45.00 + $33.75
$78.75
10 members of a bridal party need transported to a wedding reception but there are only 3 3-passenger taxis available to take them. How many will need to find other transportation?
| 3 | |
| 1 | |
| 2 | |
| 8 |
There are 3 3-passenger taxis available so that's 3 x 3 = 9 total seats. There are 10 people needing transportation leaving 10 - 9 = 1 who will have to find other transportation.