ASVAB Arithmetic Reasoning Practice Test 60563 Results

Your Results Global Average
Questions 5 5
Correct 0 2.80
Score 0% 56%

Review

1

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 10% off." If Damon buys two shirts, each with a regular price of $50, how much will he pay for both shirts?

57% Answer Correctly
$5.00
$62.50
$67.50
$95.00

Solution

By buying two shirts, Damon will save $50 x \( \frac{10}{100} \) = \( \frac{$50 x 10}{100} \) = \( \frac{$500}{100} \) = $5.00 on the second shirt.

So, his total cost will be
$50.00 + ($50.00 - $5.00)
$50.00 + $45.00
$95.00


2

What is \( \sqrt{\frac{64}{36}} \)?

70% Answer Correctly
1\(\frac{1}{3}\)
\(\frac{6}{7}\)
1\(\frac{4}{5}\)
\(\frac{4}{5}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{64}{36}} \)
\( \frac{\sqrt{64}}{\sqrt{36}} \)
\( \frac{\sqrt{8^2}}{\sqrt{6^2}} \)
\( \frac{8}{6} \)
1\(\frac{1}{3}\)


3

What is \( 4 \)\( \sqrt{48} \) - \( 8 \)\( \sqrt{3} \)

38% Answer Correctly
32\( \sqrt{48} \)
32\( \sqrt{3} \)
8\( \sqrt{3} \)
-4\( \sqrt{3} \)

Solution

To subtract these radicals together their radicands must be the same:

4\( \sqrt{48} \) - 8\( \sqrt{3} \)
4\( \sqrt{16 \times 3} \) - 8\( \sqrt{3} \)
4\( \sqrt{4^2 \times 3} \) - 8\( \sqrt{3} \)
(4)(4)\( \sqrt{3} \) - 8\( \sqrt{3} \)
16\( \sqrt{3} \) - 8\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

16\( \sqrt{3} \) - 8\( \sqrt{3} \)
(16 - 8)\( \sqrt{3} \)
8\( \sqrt{3} \)


4

Cooks are needed to prepare for a large party. Each cook can bake either 2 large cakes or 17 small cakes per hour. The kitchen is available for 3 hours and 29 large cakes and 340 small cakes need to be baked.

How many cooks are required to bake the required number of cakes during the time the kitchen is available?

41% Answer Correctly
10
8
12
13

Solution

If a single cook can bake 2 large cakes per hour and the kitchen is available for 3 hours, a single cook can bake 2 x 3 = 6 large cakes during that time. 29 large cakes are needed for the party so \( \frac{29}{6} \) = 4\(\frac{5}{6}\) cooks are needed to bake the required number of large cakes.

If a single cook can bake 17 small cakes per hour and the kitchen is available for 3 hours, a single cook can bake 17 x 3 = 51 small cakes during that time. 340 small cakes are needed for the party so \( \frac{340}{51} \) = 6\(\frac{2}{3}\) cooks are needed to bake the required number of small cakes.

Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 5 + 7 = 12 cooks.


5

What is \( \frac{1}{9} \) x \( \frac{2}{5} \)?

72% Answer Correctly
\(\frac{1}{16}\)
\(\frac{4}{49}\)
\(\frac{2}{5}\)
\(\frac{2}{45}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{1}{9} \) x \( \frac{2}{5} \) = \( \frac{1 x 2}{9 x 5} \) = \( \frac{2}{45} \) = \(\frac{2}{45}\)