| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.86 |
| Score | 0% | 57% |
20 members of a bridal party need transported to a wedding reception but there are only 3 5-passenger taxis available to take them. How many will need to find other transportation?
| 6 | |
| 8 | |
| 1 | |
| 5 |
There are 3 5-passenger taxis available so that's 3 x 5 = 15 total seats. There are 20 people needing transportation leaving 20 - 15 = 5 who will have to find other transportation.
Simplify \( \sqrt{50} \)
| 2\( \sqrt{4} \) | |
| 5\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| 7\( \sqrt{4} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{50} \)
\( \sqrt{25 \times 2} \)
\( \sqrt{5^2 \times 2} \)
5\( \sqrt{2} \)
What is \( 9 \)\( \sqrt{20} \) - \( 5 \)\( \sqrt{5} \)
| 45\( \sqrt{20} \) | |
| 4\( \sqrt{100} \) | |
| 4\( \sqrt{21} \) | |
| 13\( \sqrt{5} \) |
To subtract these radicals together their radicands must be the same:
9\( \sqrt{20} \) - 5\( \sqrt{5} \)
9\( \sqrt{4 \times 5} \) - 5\( \sqrt{5} \)
9\( \sqrt{2^2 \times 5} \) - 5\( \sqrt{5} \)
(9)(2)\( \sqrt{5} \) - 5\( \sqrt{5} \)
18\( \sqrt{5} \) - 5\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
18\( \sqrt{5} \) - 5\( \sqrt{5} \)If there were a total of 100 raffle tickets sold and you bought 2 tickets, what's the probability that you'll win the raffle?
| 12% | |
| 2% | |
| 18% | |
| 15% |
You have 2 out of the total of 100 raffle tickets sold so you have a (\( \frac{2}{100} \)) x 100 = \( \frac{2 \times 100}{100} \) = \( \frac{200}{100} \) = 2% chance to win the raffle.
A machine in a factory has an error rate of 7 parts per 100. The machine normally runs 24 hours a day and produces 9 parts per hour. Yesterday the machine was shut down for 4 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 167.4 | |
| 121 | |
| 117.2 | |
| 105.6 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{7}{100} \) x 9 = \( \frac{7 \times 9}{100} \) = \( \frac{63}{100} \) = 0.63 errors per hour
So, in an average hour, the machine will produce 9 - 0.63 = 8.37 error free parts.
The machine ran for 24 - 4 = 20 hours yesterday so you would expect that 20 x 8.37 = 167.4 error free parts were produced yesterday.