| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.85 |
| Score | 0% | 57% |
Solve 4 + (2 + 4) ÷ 3 x 3 - 32
| 1\(\frac{1}{3}\) | |
| \(\frac{5}{9}\) | |
| 1 | |
| \(\frac{6}{7}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
4 + (2 + 4) ÷ 3 x 3 - 32
P: 4 + (6) ÷ 3 x 3 - 32
E: 4 + 6 ÷ 3 x 3 - 9
MD: 4 + \( \frac{6}{3} \) x 3 - 9
MD: 4 + \( \frac{18}{3} \) - 9
AS: \( \frac{12}{3} \) + \( \frac{18}{3} \) - 9
AS: \( \frac{30}{3} \) - 9
AS: \( \frac{30 - 27}{3} \)
\( \frac{3}{3} \)
1
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for multiplication |
|
commutative property for multiplication |
|
distributive property for division |
|
commutative property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
A machine in a factory has an error rate of 7 parts per 100. The machine normally runs 24 hours a day and produces 8 parts per hour. Yesterday the machine was shut down for 4 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 182.4 | |
| 153.6 | |
| 148.8 | |
| 84.6 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{7}{100} \) x 8 = \( \frac{7 \times 8}{100} \) = \( \frac{56}{100} \) = 0.56 errors per hour
So, in an average hour, the machine will produce 8 - 0.56 = 7.4399999999999995 error free parts.
The machine ran for 24 - 4 = 20 hours yesterday so you would expect that 20 x 7.4399999999999995 = 148.8 error free parts were produced yesterday.
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 5 to 2 and the ratio of baseball to basketball cards is 5 to 1, what is the ratio of football to basketball cards?
| 9:2 | |
| 25:2 | |
| 1:6 | |
| 1:4 |
The ratio of football cards to baseball cards is 5:2 and the ratio of baseball cards to basketball cards is 5:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 25:10 and the ratio of baseball cards to basketball cards as 10:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 25:10, 10:2 which reduces to 25:2.
Find the average of the following numbers: 14, 12, 16, 10.
| 17 | |
| 13 | |
| 14 | |
| 8 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{14 + 12 + 16 + 10}{4} \) = \( \frac{52}{4} \) = 13