ASVAB Arithmetic Reasoning Practice Test 611448 Results

Your Results Global Average
Questions 5 5
Correct 0 3.39
Score 0% 68%

Review

1

4! = ?

85% Answer Correctly

4 x 3 x 2 x 1

4 x 3

5 x 4 x 3 x 2 x 1

3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


2

Solve 5 + (3 + 3) ÷ 4 x 3 - 22

52% Answer Correctly
1\(\frac{1}{3}\)
5\(\frac{1}{2}\)
\(\frac{3}{8}\)
\(\frac{3}{5}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

5 + (3 + 3) ÷ 4 x 3 - 22
P: 5 + (6) ÷ 4 x 3 - 22
E: 5 + 6 ÷ 4 x 3 - 4
MD: 5 + \( \frac{6}{4} \) x 3 - 4
MD: 5 + \( \frac{18}{4} \) - 4
AS: \( \frac{20}{4} \) + \( \frac{18}{4} \) - 4
AS: \( \frac{38}{4} \) - 4
AS: \( \frac{38 - 16}{4} \)
\( \frac{22}{4} \)
5\(\frac{1}{2}\)


3

What is \( \frac{3}{6} \) x \( \frac{1}{7} \)?

72% Answer Correctly
\(\frac{6}{35}\)
\(\frac{1}{14}\)
\(\frac{1}{4}\)
\(\frac{3}{7}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{6} \) x \( \frac{1}{7} \) = \( \frac{3 x 1}{6 x 7} \) = \( \frac{3}{42} \) = \(\frac{1}{14}\)


4

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

55% Answer Correctly

distributive property for division

commutative property for multiplication

commutative property for division

distributive property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


5

What is 8a5 x 4a4?

75% Answer Correctly
12a20
32a9
32a
32a20

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

8a5 x 4a4
(8 x 4)a(5 + 4)
32a9