ASVAB Arithmetic Reasoning Practice Test 612006 Results

Your Results Global Average
Questions 5 5
Correct 0 3.25
Score 0% 65%

Review

1

If there were a total of 100 raffle tickets sold and you bought 3 tickets, what's the probability that you'll win the raffle?

60% Answer Correctly
4%
3%
7%
17%

Solution

You have 3 out of the total of 100 raffle tickets sold so you have a (\( \frac{3}{100} \)) x 100 = \( \frac{3 \times 100}{100} \) = \( \frac{300}{100} \) = 3% chance to win the raffle.


2

What is \( \sqrt{\frac{4}{16}} \)?

70% Answer Correctly
1
\(\frac{7}{8}\)
\(\frac{1}{4}\)
\(\frac{1}{2}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{4}{16}} \)
\( \frac{\sqrt{4}}{\sqrt{16}} \)
\( \frac{\sqrt{2^2}}{\sqrt{4^2}} \)
\(\frac{1}{2}\)


3

Simplify \( \sqrt{28} \)

62% Answer Correctly
2\( \sqrt{7} \)
6\( \sqrt{14} \)
8\( \sqrt{14} \)
6\( \sqrt{7} \)

Solution

To simplify a radical, factor out the perfect squares:

\( \sqrt{28} \)
\( \sqrt{4 \times 7} \)
\( \sqrt{2^2 \times 7} \)
2\( \sqrt{7} \)


4

Simplify \( \frac{32}{80} \).

77% Answer Correctly
\( \frac{2}{5} \)
\( \frac{8}{11} \)
\( \frac{5}{19} \)
\( \frac{8}{19} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 32 are [1, 2, 4, 8, 16, 32] and the factors of 80 are [1, 2, 4, 5, 8, 10, 16, 20, 40, 80]. They share 5 factors [1, 2, 4, 8, 16] making 16 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{32}{80} \) = \( \frac{\frac{32}{16}}{\frac{80}{16}} \) = \( \frac{2}{5} \)


5

If all of a roofing company's 16 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?

55% Answer Correctly
7
2
12
8

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 16 workers at the company now and that's enough to staff 4 crews so there are \( \frac{16}{4} \) = 4 workers on a crew. 6 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 6 x 4 = 24 total workers to staff the crews during the busy season. The company already employs 16 workers so they need to add 24 - 16 = 8 new staff for the busy season.