To add these radicals together their radicands must be the same:

9\( \sqrt{125} \) + 9\( \sqrt{5} \)
9\( \sqrt{25 \times 5} \) + 9\( \sqrt{5} \)
9\( \sqrt{5^2 \times 5} \) + 9\( \sqrt{5} \)
(9)(5)\( \sqrt{5} \) + 9\( \sqrt{5} \)
45\( \sqrt{5} \) + 9\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 54 meters so the equation becomes: 2w + 2h = 54.

Putting these two equations together and solving for width (w):

2w + 2h = 54
w + h = \( \frac{54}{2} \)
w + h = 27
w = 27 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 27 - 2w
3w = 27
w = \( \frac{27}{3} \)
w = 9

Since h = 2w that makes h = (2 x 9) = 18 and the area = h x w = 9 x 18 = 162 m²

The factors of a number are all positive integers that divide evenly into the number. The factors of 28 are 1, 2, 4, 7, 14, 28.

If 50% of the town's 44,000 voters cast ballots the number of votes cast is:

(\( \frac{50}{100} \)) x 44,000 = \( \frac{2,200,000}{100} \) = 22,000

The mayor got 62% of the votes cast which is:

(\( \frac{62}{100} \)) x 22,000 = \( \frac{1,364,000}{100} \) = 13,640 votes.

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 30 x \( \frac{65}{100} \) = \( \frac{65 x 30}{100} \) = \( \frac{1950}{100} \) = 19 shots

The center makes 45% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{19}{\frac{45}{100}} \) = 19 x \( \frac{100}{45} \) = \( \frac{19 x 100}{45} \) = \( \frac{1900}{45} \) = 42 shots

to make the same number of shots as the guard and thus score the same number of points.