ASVAB Arithmetic Reasoning Practice Test 614520 Results

Your Results Global Average
Questions 5 5
Correct 0 3.22
Score 0% 64%

Review

1

A circular logo is enlarged to fit the lid of a jar. The new diameter is 65% larger than the original. By what percentage has the area of the logo increased?

51% Answer Correctly
37\(\frac{1}{2}\)%
30%
27\(\frac{1}{2}\)%
32\(\frac{1}{2}\)%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 65% the radius (and, consequently, the total area) increases by \( \frac{65\text{%}}{2} \) = 32\(\frac{1}{2}\)%


2

What is the least common multiple of 5 and 9?

73% Answer Correctly
4
25
45
19

Solution

The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 5 and 9 have in common.


3

If \( \left|z - 5\right| \) + 1 = 4, which of these is a possible value for z?

62% Answer Correctly
8
-3
-2
5

Solution

First, solve for \( \left|z - 5\right| \):

\( \left|z - 5\right| \) + 1 = 4
\( \left|z - 5\right| \) = 4 - 1
\( \left|z - 5\right| \) = 3

The value inside the absolute value brackets can be either positive or negative so (z - 5) must equal + 3 or -3 for \( \left|z - 5\right| \) to equal 3:

z - 5 = 3
z = 3 + 5
z = 8
z - 5 = -3
z = -3 + 5
z = 2

So, z = 2 or z = 8.


4

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

least common multiple

absolute value

greatest common multiple

greatest common factor


Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.


5

Solve for \( \frac{3!}{2!} \)

67% Answer Correctly
3
210
5
\( \frac{1}{9} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{2!} \)
\( \frac{3 \times 2 \times 1}{2 \times 1} \)
\( \frac{3}{1} \)
3