Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (5 + 2) ÷ 4 x 5 - 2²
P: 3 + (7) ÷ 4 x 5 - 2²
E: 3 + 7 ÷ 4 x 5 - 4
MD: 3 + \( \frac{7}{4} \) x 5 - 4
MD: 3 + \( \frac{35}{4} \) - 4
AS: \( \frac{12}{4} \) + \( \frac{35}{4} \) - 4
AS: \( \frac{47}{4} \) - 4
AS: \( \frac{47 - 16}{4} \)
\( \frac{31}{4} \)
7\(\frac{3}{4}\)

First, solve for \( \left|c + 5\right| \):

\( \left|c + 5\right| \) - 4 = -7
\( \left|c + 5\right| \) = -7 + 4
\( \left|c + 5\right| \) = -3

The value inside the absolute value brackets can be either positive or negative so (c + 5) must equal - 3 or --3 for \( \left|c + 5\right| \) to equal -3:

So, c = -2 or c = -8.

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{93}{16} \) = 5\(\frac{13}{16}\)

So, it will take 5 full vans and one partially full van to transport the entire team making a total of 6 vans.

There are 3 2-passenger taxis available so that's 3 x 2 = 6 total seats. There are 9 people needing transportation leaving 9 - 6 = 3 who will have to find other transportation.

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 500 meters to kilometers, divide the distance by 1000 to get 0.5km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.5km + 40.5km + 14.0km
total distance = 55km