| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.52 |
| Score | 0% | 70% |
The total water usage for a city is 40,000 gallons each day. Of that total, 29% is for personal use and 64% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 14,000 | |
| 6,000 | |
| 14,400 | |
| 3,000 |
64% of the water consumption is industrial use and 29% is personal use so (64% - 29%) = 35% more water is used for industrial purposes. 40,000 gallons are consumed daily so industry consumes \( \frac{35}{100} \) x 40,000 gallons = 14,000 gallons.
What is the distance in miles of a trip that takes 5 hours at an average speed of 60 miles per hour?
| 120 miles | |
| 260 miles | |
| 300 miles | |
| 100 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 60mph \times 5h \)
300 miles
What is (b5)5?
| b25 | |
| b0 | |
| b10 | |
| 5b5 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(b5)5Solve for \( \frac{5!}{2!} \)
| 120 | |
| 20 | |
| 60 | |
| \( \frac{1}{72} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{5!}{2!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{5 \times 4 \times 3}{1} \)
\( 5 \times 4 \times 3 \)
60
What is \( \frac{7}{3} \) - \( \frac{6}{5} \)?
| 2 \( \frac{3}{8} \) | |
| \( \frac{5}{11} \) | |
| 1 \( \frac{1}{10} \) | |
| 1\(\frac{2}{15}\) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50]. The first few multiples they share are [15, 30, 45, 60, 75] making 15 the smallest multiple 3 and 5 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{7 x 5}{3 x 5} \) - \( \frac{6 x 3}{5 x 3} \)
\( \frac{35}{15} \) - \( \frac{18}{15} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{35 - 18}{15} \) = \( \frac{17}{15} \) = 1\(\frac{2}{15}\)