ASVAB Arithmetic Reasoning Practice Test 616032 Results

Your Results Global Average
Questions 5 5
Correct 0 3.58
Score 0% 72%

Review

1

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

distributive property for multiplication

commutative property for multiplication

distributive property for division

commutative property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


2

Find the average of the following numbers: 18, 10, 15, 13.

75% Answer Correctly
14
18
9
10

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{18 + 10 + 15 + 13}{4} \) = \( \frac{56}{4} \) = 14


3

What is -c5 - 8c5?

71% Answer Correctly
7c5
-9c5
9c-5
9c5

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

-1c5 - 8c5
(-1 - 8)c5
-9c5


4

What is the distance in miles of a trip that takes 8 hours at an average speed of 40 miles per hour?

87% Answer Correctly
90 miles
520 miles
540 miles
320 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 40mph \times 8h \)
320 miles


5

What is \( \sqrt{\frac{9}{36}} \)?

70% Answer Correctly
\(\frac{1}{2}\)
1\(\frac{1}{2}\)
2
2\(\frac{1}{2}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{9}{36}} \)
\( \frac{\sqrt{9}}{\sqrt{36}} \)
\( \frac{\sqrt{3^2}}{\sqrt{6^2}} \)
\(\frac{1}{2}\)