| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.09 |
| Score | 0% | 62% |
If \( \left|b + 6\right| \) + 1 = 9, which of these is a possible value for b?
| 24 | |
| -14 | |
| 6 | |
| -8 |
First, solve for \( \left|b + 6\right| \):
\( \left|b + 6\right| \) + 1 = 9
\( \left|b + 6\right| \) = 9 - 1
\( \left|b + 6\right| \) = 8
The value inside the absolute value brackets can be either positive or negative so (b + 6) must equal + 8 or -8 for \( \left|b + 6\right| \) to equal 8:
| b + 6 = 8 b = 8 - 6 b = 2 | b + 6 = -8 b = -8 - 6 b = -14 |
So, b = -14 or b = 2.
Convert c-4 to remove the negative exponent.
| \( \frac{1}{c^4} \) | |
| \( \frac{-1}{-4c^{4}} \) | |
| \( \frac{1}{c^{-4}} \) | |
| \( \frac{-1}{c^{-4}} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
Frank loaned Frank $200 at an annual interest rate of 4%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $24 | |
| $30 | |
| $8 | |
| $63 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $200
i = 0.04 x $200
i = $8
If all of a roofing company's 8 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?
| 9 | |
| 4 | |
| 16 | |
| 5 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 8 workers at the company now and that's enough to staff 4 crews so there are \( \frac{8}{4} \) = 2 workers on a crew. 6 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 6 x 2 = 12 total workers to staff the crews during the busy season. The company already employs 8 workers so they need to add 12 - 8 = 4 new staff for the busy season.
How many 1 gallon cans worth of fuel would you need to pour into an empty 4 gallon tank to fill it exactly halfway?
| 2 | |
| 4 | |
| 8 | |
| 9 |
To fill a 4 gallon tank exactly halfway you'll need 2 gallons of fuel. Each fuel can holds 1 gallons so:
cans = \( \frac{2 \text{ gallons}}{1 \text{ gallons}} \) = 2