| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.11 |
| Score | 0% | 62% |
What is 9\( \sqrt{8} \) x 5\( \sqrt{6} \)?
| 14\( \sqrt{6} \) | |
| 180\( \sqrt{3} \) | |
| 45\( \sqrt{6} \) | |
| 45\( \sqrt{14} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
9\( \sqrt{8} \) x 5\( \sqrt{6} \)
(9 x 5)\( \sqrt{8 \times 6} \)
45\( \sqrt{48} \)
Now we need to simplify the radical:
45\( \sqrt{48} \)
45\( \sqrt{3 \times 16} \)
45\( \sqrt{3 \times 4^2} \)
(45)(4)\( \sqrt{3} \)
180\( \sqrt{3} \)
How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 15 gallon tank to fill it exactly halfway?
| 5 | |
| 10 | |
| 6 | |
| 9 |
To fill a 15 gallon tank exactly halfway you'll need 7\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:
cans = \( \frac{7\frac{1}{2} \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 5
If \(\left|a\right| = 7\), which of the following best describes a?
a = -7 |
|
a = 7 |
|
a = 7 or a = -7 |
|
none of these is correct |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).
Solve for \( \frac{2!}{6!} \)
| \( \frac{1}{1680} \) | |
| \( \frac{1}{8} \) | |
| \( \frac{1}{5} \) | |
| \( \frac{1}{360} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{6!} \)
\( \frac{2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5 \times 4 \times 3} \)
\( \frac{1}{360} \)
How many hours does it take a car to travel 45 miles at an average speed of 15 miles per hour?
| 5 hours | |
| 8 hours | |
| 4 hours | |
| 3 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{45mi}{15mph} \)
3 hours