ASVAB Arithmetic Reasoning Practice Test 623452 Results

Your Results Global Average
Questions 5 5
Correct 0 3.03
Score 0% 61%

Review

1

On average, the center for a basketball team hits 50% of his shots while a guard on the same team hits 65% of his shots. If the guard takes 30 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?

42% Answer Correctly
33
38
59
36

Solution
If the guard hits 65% of his shots and takes 30 shots he'll make:

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 30 x \( \frac{65}{100} \) = \( \frac{65 x 30}{100} \) = \( \frac{1950}{100} \) = 19 shots

The center makes 50% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{19}{\frac{50}{100}} \) = 19 x \( \frac{100}{50} \) = \( \frac{19 x 100}{50} \) = \( \frac{1900}{50} \) = 38 shots

to make the same number of shots as the guard and thus score the same number of points.


2

Damon loaned Jennifer $1,400 at an annual interest rate of 3%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$1,442
$1,484
$1,456
$1,512

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,400
i = 0.03 x $1,400

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $1,400 + $42
total = $1,442


3

Solve for \( \frac{4!}{5!} \)

66% Answer Correctly
60480
6720
504
\( \frac{1}{5} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{4!}{5!} \)
\( \frac{4 \times 3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5} \)
\( \frac{1}{5} \)


4

A machine in a factory has an error rate of 7 parts per 100. The machine normally runs 24 hours a day and produces 6 parts per hour. Yesterday the machine was shut down for 9 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
213.4
83.7
116.4
99.4

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{7}{100} \) x 6 = \( \frac{7 \times 6}{100} \) = \( \frac{42}{100} \) = 0.42 errors per hour

So, in an average hour, the machine will produce 6 - 0.42 = 5.58 error free parts.

The machine ran for 24 - 9 = 15 hours yesterday so you would expect that 15 x 5.58 = 83.7 error free parts were produced yesterday.


5

What is \( \frac{4}{6} \) x \( \frac{2}{6} \)?

72% Answer Correctly
\(\frac{4}{27}\)
\(\frac{2}{9}\)
1\(\frac{1}{3}\)
\(\frac{1}{7}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{6} \) x \( \frac{2}{6} \) = \( \frac{4 x 2}{6 x 6} \) = \( \frac{8}{36} \) = \(\frac{2}{9}\)